Ethylene oxide as a vapor and water as liquid

Ethylene oxide as a vapor and water as liquid, both at 25°C and 101.33 kPa, react to form a liquid solution containing ethylene glycol (1,2-ethanediol) at the same conditions:
((CH2)2O + H2O → CH2OH.CH2OH
If the initial molar ratio of ethylene oxide to water is 3.0, estimate the equilibrium conversion of ethylene oxide to ethylene glycol.
At equilibrium the system consists of liquid and vapor in equilibrium, and the intensive state of the system is fixed by the specification of T and P. Therefore, one must first determine the phase compositions, independent of the ratio of reactants. These results may then be applied in the material-balance equations to find the equilibrium conversion.
Choose as standard states for water and ethylene glycol the pure liquids at 1 bar and for ethylene oxide the pure ideal gas at 1 bar. Assume any water present in the liquid - phase has an activity coefficient of unity and that the vapor phase is an ideal gas. The partial pressure of ethylene oxide over the liquid phase is given by:
Pi/kPa = 415 xj
The vapor pressure of ethylene glycol at 25°C is so low that its concentration in the vapor phase is negligible.


Answer:

 

13.39Phase-equilibrium equations:

Ethylene oxide(1): p1 = y1∙P = 415∙x1

P := 101.33∙kPa

 

Water (2): x2∙Psat2 = y2 ∙ P

Psat2 : = 3.166∙kPa

 

Ethylene glycol(3): Psat3 = 0.0 y3 = 0.0

 

Therefore, y2 = 1 - y1 and x3 = 1 - x2 - x3

 

For the specified standard states:

(CH2)2O (g) + H2O(l) = CH2OH.CH2OH(l)

 

By Eq. (13.40) and the stated assumptions,

T:= 298.15∙kelvin

 

Data from Table C.4:

 

k = 6.018x1012

 

So large a value of k requires either y1 or x2 to approach zero if y1 approaches zero, y2 approaches unity, and the phase-equilibrium expression for water (2) makes x2 = 32, which is impossible. Thus x2 must approach zero, and the phase-equilibrium equation requires y2 also to approach zero. This means that for all practical purposes the reaction goes to completion. For initial amounts of 3 moles of ethylene oxide and 1 mole of water, the water present is entirely reacted along with 1 mole of the ethylene oxide. Conversion of the oxide is therefore 33.3 %.



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